36x^2-3x-14=0

Solution for 36x^2-3x-14=0 equation:

36x^2-3x-14=0

a = 36; b = -3; c = -14;
Δ = b2-4ac
Δ = -32-4·36·(-14)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-45}{2*36}=\frac{-42}{72}
=-7/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+45}{2*36}=\frac{48}{72}
=2/3
$